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A2Z Sheet

183. Sort a stack using recursion

Medium
Step 7: Recursion [PatternWise]›Get a Strong Hold

Sort a stack using recursion

MediumFunction: sortAStackUsingRecursion()
ASCI Mission Breakdown • Simple as Hell
"Master Sort a stack using recursion: Take `nums` (number[]), execute an optimal get a strong hold strategy, and return number[] with clean edge-case handling."
Real-World Metaphor:

Think of Sort a stack using recursion as an everyday real-world challenge: you receive input data, inspect its elements in sequence without making unnecessary duplicate passes, and transform the collection to reach the exact target without wasting computer memory.

Interactive Visual WalkthroughSTACK-QUEUE
Step 1 / 3
StatusInitialized
ModeScanning
Evaluating

1. Initialize State for Sort a stack using recursion

Load inputs and initialize algorithmic registers.

How to Think About This (Mental Model)

  1. Unpack the problem parameters (`nums` (number[])) and clarify what is given vs what must be returned.
  2. Identify the optimal data structure or pattern (e.g. pointers, hash map, or stack) to avoid redundant recalculations.
  3. Walk through state transitions, handle edge cases (empty collections, single items, negative numbers), and return the verified result.

Given an array of integers `nums`, sort the array in ascending order using the **Sort a stack using recursion** technique. Return the sorted array.

Examples

Example 1
Input: nums = [5,2,3,1]
Output: [1,2,3,5]
Example 2
Input: nums = [5,1,1,2,0,0]
Output: [0,0,1,1,2,5]

Constraints

  • 1 <= nums.length <= 5 * 10^4
  • -5 * 10^4 <= nums[i] <= 5 * 10^4
Topic Tags:
Recursion [PatternWise]Get a Strong HoldsortAStackUsingRecursion
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