"Master Count all Digits of a Number: Take `nums` (number[]), execute an optimal know basic maths strategy, and return number with clean edge-case handling."
Real-World Metaphor:
Think of Count all Digits of a Number as an everyday real-world challenge: you receive input data, inspect its elements in sequence without making unnecessary duplicate passes, and transform the collection to reach the exact target without wasting computer memory.
Interactive Visual WalkthroughFLOW-DIAGRAM
Step 1 / 3
StatusInitialized
ModeScanning
Evaluating
1. Initialize State for Count all Digits of a Number
Load inputs and initialize algorithmic registers.
How to Think About This (Mental Model)
Unpack the problem parameters (`nums` (number[])) and clarify what is given vs what must be returned.
Identify the optimal data structure or pattern (e.g. pointers, hash map, or stack) to avoid redundant recalculations.
Walk through state transitions, handle edge cases (empty collections, single items, negative numbers), and return the verified result.
### The Mission
Welcome to **Count all Digits of a Number**! In this challenge, your goal is to write a high-performance, clean solution in your chosen programming language.
You are given `nums` (number[]). Your job is to process this input using optimal logic and return number.
### How to Approach It
- Read through the inputs carefully and look for patterns.
- Think about what state you need to track as you examine each element.
- Strive for optimal time complexity and keep your code readable and structured.
Examples
Example 1
Input: nums = [1,2,3,4,5]
Output: 15
Constraints
1 <= nums.length <= 10^5
-10^9 <= nums[i] <= 10^9
Topic Tags:
Learn the basicsKnow Basic MathscountAllDigitsOfANumber